In the reaction ₁²H+₁³H+₂⁴He+₀¹n, if the binding energies of ₁²H,₁³H and ₂⁴He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is

Options

(a) a+b+c
(b) a+b-c
(c) c-a-b
(d) c+a-b

Correct Answer:

c-a-b

Explanation:

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