Navigate

In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced

In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced is 20 V. The inductance L is

Options

(a) 62.5 mH
(b) 625 mH
(c) 6.25 mH
(d) 0.625 mH

Correct Answer:

62.5 mH

Explanation:

Induced e.m.f. |e| = L (dI / dt) = L(18 – 2) / 0.05 or,

L = (20 × 0.05) / 16 = 0.0625 H = 62.5 mH

OA2006
admin:

Related Questions

  1. The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
  2. An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
  3. The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
  4. An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
  5. The temperature of a body falls from 50⁰C to 40⁰C in 10 minute. If the temperature