In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is

Options

(a) 10
(b) 7
(c) 6
(d) 4

Correct Answer:

4

Explanation:

We know, pOH = pK(b) + log{[B⁻]/[HB]},

Since, [B⁻] = [HB] (given).

Therefore pOH = pK(b) ⇒ pOH = 10,

Therefore pH = 14 – 10 = 4.