In a buffer solution containing equal concentration of B⁻ and HB,

In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is

(a) 10
(b) 7
(c) 6
(d) 4

We know, pOH = pK(b) + log{[B⁻]/[HB]},

Since, [B⁻] = [HB] (given).

Therefore pOH = pK(b) ⇒ pOH = 10,

Therefore pH = 14 – 10 = 4.

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