If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum

If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum intensity and minimum intensity is

(a) (9:1)
(b) (1:9)
(c) (4:1)
(d) (1:4)

(9:1)

Let ɑ and b the amplitude of wave.

Given: ɑ / b = 2 / 1 (or) ɑ = 2b

I(max) / I(min) = (ɑ + b)² / (ɑ – b)² = 9 / 1

admin: