If the radius of star is R and it acts as a black body, what would be the temperature

If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?

Options

(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴

Correct Answer:

(Q / 4 πR²σ)¹/⁴

Explanation:

Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²

admin:

Related Questions

  1. The intensity at the maximum in a Young’s double slit experiment is I₀.
  2. A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm
  3. A potentiometer wire of length 10 m and resistance 10 Ω per metre is connected in series
  4. In a potentiometer experiment two cells of e.m.f. E₁ and E₂ are used in series
  5. If two charges +4e and +e are at a distance x apart, then at what distance charge q