If the radius of star is R and it acts as a black body, what would be the temperature

If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?

Options

(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴

Correct Answer:

(Q / 4 πR²σ)¹/⁴

Explanation:

Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²

admin:

Related Questions

  1. An electron is
  2. The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
  3. Which of the following will be σ if Y=2.4 η?
  4. The induced emf in a coil of 10 H inductance in which current varies
  5. Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle