If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is

Options

(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H

Correct Answer:

2×10⁻³ H

Explanation:

Induced emf, e = 2 V

i₁ = 8 A, i₂ = 6 A

∆t = 2 × 10⁻³ s

Coefficient of self-induction, L = e / (∆i/∆t)

= -2 / [(6-2) / 2 × 10⁻³]

= (-2 × 2 × 10⁻³) / -2

= 2 × 10⁻³ H