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If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04%

If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is

Options

(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O

Correct Answer:

CHClO

Explanation:

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AIIMS1998
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