How much work is required to carry a 6 μC charge from the negative terminal to the positive terminal of a 9V battery?
Options
(a) 54×10⁻³ J
(b) 54×10⁻⁶ J
(c) 54×10⁻¹⁹ J
(d) 54×10⁻¹² J
Correct Answer:
54×10⁻⁶ J
Explanation:
Work done = q × V = (6 × 10⁻⁶) × 6 = 54 × 10⁻⁶ J