For photoelectric emission from certain metal the cut-off frequency is v

For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

Options

(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)

Correct Answer:

√ 2hv / m

Explanation:

From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m

admin:

Related Questions

  1. In common base mode of a transistor, the collector current is 5.488 mA
  2. The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
  3. Which one of the following statements is true, if half-life of a radioactive substance
  4. What is the dimension of impedance?
  5. The phenomenon of radioactivity