For a simple pendulum performing simple harmonic motion, the time period

For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be

Options

(a) straight line
(b) circle
(c) parabola
(d) ellipse

Correct Answer:

parabola

Explanation:

Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.

admin:

Related Questions

  1. A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
  2. A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
  3. An electric motor operating on a 60 volt D.C supply draws a current of 10 amp.
  4. Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
  5. The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.