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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by

An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be

Options

(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s

Correct Answer:

2 s

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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