Navigate

An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.

An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of

Options

(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm

Correct Answer:

10⁻¹² cm

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

AIEEE2004
admin:

Related Questions

  1. If a body travels half the distance with velocity v1 and the next half with velocity v2
  2. At place on earth, the vertical component of earth’s magnetic field is √3 times
  3. Two spheres A and B of masses m and m respectively collide. A is at rest initially
  4. A lens having focal length f and aperture of diameter d forms an image of intensity I
  5. Water rises to a height h in capillary tube. If the length of capillary tube above