A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is

Options

(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹

Correct Answer:

2.5×10⁻⁴ Vs⁻¹

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.