A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane motion, the proton will move in a circular path of radius

Options

(a) 2Em/qB
(b) √2Em/qB
(c) √Em/2qB
(d) √2Eq/qB

Correct Answer:

√2Em/qB

Explanation:

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