A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state

A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state after few microseconds another photon of energy 15 eV collides inelastically with same hydrogen atom. Finally by a suitable detector we find

Options

(a) photon of energy 3.4 eV and electron of energy 1.4 eV
(b) photon of energy 10.2 eV and electron of energy 1.4 eV
(c) two photons of energy 3.4 eV
(d) two photons of energy 10.2 eV

Correct Answer:

photon of energy 10.2 eV and electron of energy 1.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
  2. The dimensional formula for Boltzmann’s constant is
  3. The control rods used in a nuclear reactor can be made up of
  4. The liquid-crystal phase of a matter is called
  5. The purpose of using heavy water in nuclear reactor is