A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state

A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state after few microseconds another photon of energy 15 eV collides inelastically with same hydrogen atom. Finally by a suitable detector we find

Options

(a) photon of energy 3.4 eV and electron of energy 1.4 eV
(b) photon of energy 10.2 eV and electron of energy 1.4 eV
(c) two photons of energy 3.4 eV
(d) two photons of energy 10.2 eV

Correct Answer:

photon of energy 10.2 eV and electron of energy 1.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
  2. A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change
  3. The total energy of an electron in the first excited state of hydrogen atom
  4. The sum of the magnitudes of two forces acting at a point is 16 N
  5. In n-type semiconductor, electrons are majority charge carriers