A particle of mass m is projected with velocity v making an angle of 45° with

A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be:

Options

(a) 2mv
(b) mv/√2
(c) mv√2
(d) zero

Correct Answer:

mv√2

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. In Young’s double slit experiment, a third slit is made in between the double slits.
  2. What is the energy of photon whose wavelength is 6840 Å?
  3. The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
  4. Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
  5. When ultraviolet rays are incident on metal plate, then photoelectric effect