A particle executing simple harmonic motion of amplitude 5 cm has maximum

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

Options

(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz

Correct Answer:

1 Hz

Explanation:

a = 5 cm, vₘₐₓ = 31.4 cm/s

vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5

⇒ 31.4 = 10 × 31.4 × ʋ

⇒ ʋ = 1 Hz

admin:

Related Questions

  1. Velocities of sound measured in hydrogen and oxygen gas at a given temperature
  2. Which one of the following statements is WRONG in the context of X-rays generated
  3. A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
  4. A conducting sphere of radius R is given a charge Q. The electric potential
  5. A bar magnet of moment of inertia I is vibrated in a magnetic field of induction