A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be

Options

(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV

Correct Answer:

0.49 eV

Explanation:

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