A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is

Options

(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj

Correct Answer:

530 mj

Explanation:

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