Navigate

A common emitter amplifier is designed with n-p-n transistor (α=0.99).

A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be

Options

(a) 9900
(b) 99
(c) 9.9
(d) 990

Correct Answer:

990

Explanation:

Voltage gain = β × Resistance gain

β = α/(1-α) = 0.99 / (1-0.99) = 99

Resistance gain = (10 × 10³) = 10

Voltage gain = 99 × 10 = 990

ML2015
admin:

Related Questions

  1. The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
  2. There are four light-weight-rod samples A,B,C,D seperately suspended by threads
  3. The energy required to charge a parallel plate condenser of plate separation d
  4. Two Carnot engine A and B are operated in series. The engine A receives
  5. The equivalent resistance of two resistors connected in series is 6 Ω