A boy standing at top of a tower of 20 m height drops a stone

A boy standing at top of a tower of 20 m height drops a stone.assuming g=10 ms⁻²,the velocity with which it hits the ground is

Options

(a) 20 m/s
(b) 40 m/s
(c) 5 m/s
(d) 10 m/s

Correct Answer:

20 m/s

Explanation:

Let, v²=u²+2gh
v= is the final velocity
u= is the initial velocity
g= is the acceleration
h= is the distance
Then, u =0
.·. v²=0²+2gh
v=√2gh
Given, g=10 m/s², h=20 m
.·. v=√2x10x20
v=20 m.

admin:

Related Questions

  1. A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
  2. In radioactive element, β-rays are emitted from
  3. If a proton, a deuteron and an alpha particle, on being accelerated by the same
  4. Time period of the rotation of the earth about its own axis is 24 hour
  5. The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle