A boy standing at top of a tower of 20 m height drops a stone

A boy standing at top of a tower of 20 m height drops a stone.assuming g=10 ms⁻²,the velocity with which it hits the ground is

Options

(a) 20 m/s
(b) 40 m/s
(c) 5 m/s
(d) 10 m/s

Correct Answer:

20 m/s

Explanation:

Let, v²=u²+2gh
v= is the final velocity
u= is the initial velocity
g= is the acceleration
h= is the distance
Then, u =0
.·. v²=0²+2gh
v=√2gh
Given, g=10 m/s², h=20 m
.·. v=√2x10x20
v=20 m.

admin:

Related Questions

  1. A stone is tied to a string of length l and whirled in a vertical circle with the other end
  2. In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
  3. An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
  4. The approximate depth of an ocean is 2700 m. The compressibility of water is
  5. If critical angle for a material to air passage is 30°, the refractive index