A boy standing at top of a tower of 20 m height drops a stone

A boy standing at top of a tower of 20 m height drops a stone.assuming g=10 ms⁻²,the velocity with which it hits the ground is

Options

(a) 20 m/s
(b) 40 m/s
(c) 5 m/s
(d) 10 m/s

Correct Answer:

20 m/s

Explanation:

Let, v²=u²+2gh
v= is the final velocity
u= is the initial velocity
g= is the acceleration
h= is the distance
Then, u =0
.·. v²=0²+2gh
v=√2gh
Given, g=10 m/s², h=20 m
.·. v=√2x10x20
v=20 m.

admin:

Related Questions

  1. Which one of the following electrical meter has the smallest resistance?
  2. In Young’s double slit experiment, the wavelength of the light used is doubled
  3. The input characteristics of a transistor in CE mode is the graph obtained by plotting
  4. If the red light is replaced by blue light illuminating the object in a microscope
  5. If vₑ is escape velocity and vₙ is orbital velocity of a satellite