A boy playing on the roof of a 10m high building throws a ball with a speed of 10 m/s at an angle of 30⁰ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground(g=10 ms⁻²)?
Options
(a) 8.66 m
(b) 5.20 m
(c) 4.33 m
(d) 2.60 m
Correct Answer:
8.66 m
Explanation:
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R=u^2sin2@/g
R=10^2*sin(2*30°)/10
R=10*sin(60°)
R=10√3/2
R=5√3
R=8.66m