1 c.c N₂O at NTP contains
Options
(a) (1.8/224) x 10²² atoms
(b) (6.02/22400) x 10²³ molecules
(c) (1.32/224) x 10²³ electrons
(d) all the above
Correct Answer:
all the above
Explanation:
At N.T.P 22400 cc of N₂O =6.02 x 10²³ molecules
1 cc contains = (6.02 x 10²³) / 22400 molecules
N₂O contains 3 atoms, so
= (3 x 6.02 x 10²³) / 22400 atoms
=1.8 / 224 x 10²² atoms
No of electrons in N₂O = (7*2)+8 =22
= (22 x 6.02 x 10²³) / 22400 electrons
=132.44 x 10²³ / 22400 electrons
=1.32 x 10²³ / 224 electrons
View Comments (2)
It is totally wrong answer ok.its answer is (b)part ok what are you doing.Can you explain why are you uploading the wrong answers.Please check the answer
kindly read the explanation. all options are correct answers as each option is in different units. so (d) is the correct answer.