When x litres hydrogen and chlorine are mixed, moles of HCl is

When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to

(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)

1 mol of Hcl(g)

1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole

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