When two identical capacitors are in series, they have 3 μF capacitance and when in parallel 12 μF. What is the capacitance of each?
Options
(a) 6 μF
(b) 3 μF
(c) 12 μF
(d) 9 μF
Correct Answer:
6 μF
Explanation:
Let C = each capacitance
In parallel, (C + C) = 12 ⇒ 2C = 12
⇒ C = 6 μF