When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of pyridine the product obtained is
Options
(a) CH₃CH₂Cl + HCl
(b) CH₃CH₂Cl + H₂O + SO₂
(c) CH₃CH₂Cl + Cl₂ + SO₂
(d) C₂H₅Cl + HCl + SO₂
Correct Answer:
C₂H₅Cl + HCl + SO₂
Explanation:
C₂H₅OH + SOCl₂ → C₂H₅Cl + HCl + SO₂.