Navigate

When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm

When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm from the lens. The focal length and power of lens are

Options

(a) F=-20 cm, P=-5 D
(b) F=-40 cm, P=-5 D
(c) F=-40 cm, P=-2.5 D
(d) F=-20 cm, P=-2.5 D

Correct Answer:

F=-40 cm, P=-2.5 D

Explanation:

We have, 1 / f = (1/v) – (1/u) ⇒ 1 / f = (1/-20) – (-1/40) = (-1 + 1) / 40 = 1 / 40

f = – 40 cm

Power of the lens, P = – (200 / 0.40) = – 2.5 D

JK2013
admin:

Related Questions

  1. The power factor of an AC circuit having resistance R and inductance L connected
  2. A particle is moving in a circle with uniform speed v. In moving from a point to another
  3. Two particles are oscillating along the same line with the same frequency
  4. The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
  5. Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.