When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,

When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸, the emitted particles will be

Options

(a) neutrons
(b) alpha particles
(c) beta particles
(d) gamma photons

Correct Answer:

gamma photons

Explanation:

₃Li⁷ + ₁H¹ → ₂Be⁴ + zX ᴬ
Z for the unknown X nucleus = 3 + 1 – 4 = 0
A for the unknown X nucleus = 7 + 1 – 8 = 0
Hence particle emitted has zero Z and zero A
It is a gamma photon.

admin:

Related Questions

  1. The angle of incidence for a ray of light at a refracting surface of a prism is 45⁰.
  2. When the disc rotates with uniform angulr velocity.Which of the following is not true?
  3. The breaking stress of a wire depends upon
  4. Energy in a current carrying coil is stored in the form of
  5. A solid sphere, disc and solid cylinder all of the same mass and made up of same material