Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂

Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂ .On collision, one of the particle s get excited to higher level, after absorbing energy E.If final velocities of particles be v₁ and v₂, then we must have

Options

(a) m₁²u₁+ m₂²u₂ -E = m₁²v₁+ m₂²v₂
(b) 1/2 m₁u₁²+m₂ u₂² = 1/2 m₁v₁²+ 1/2 m₂v₂² -E
(c) 1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²
(d) 1/2 m₁u₁²+m₂ u₂² +E = 1/2 m₁v₁²+ 1/2 m₂v₂²

Correct Answer:

1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
  2. A spherical conductor of radius 2 m is charged to a potential of 120 V. It is now
  3. A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
  4. An atom bomb works on the principle of
  5. Imagine a light planet revolving around a very massive star in a circular