The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³

The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1atm = 101.32 J)

(a) -6 J
(b) -608 J
(c) ⁺304 J
(d) -304 J

-608 J

Work = -P(ext) x volume change =
-3 x 101.32 x (6 – 4)
= -6 x 101.32 = -607.92 J = -608 J

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