The volume occupies by one molecules of water is [density of water =1g/cm³

The volume occupies by one molecules of water is [density of water =1g/cm³

Options

(a) 22400 cm³
(b) 6.02 ˣ 10⁻²³cm³
(c) 3.0 ˣ 10⁻²³cm³
(d) 11200cm³

Correct Answer:

3.0 ˣ 10⁻²³cm³

Explanation:

Given density of water = 1 g/cm³, Therefore 1 g of H₂O₂ = 1 cm³ of H₂O, 1 mole of water = 18 g of H₂O = 18 cm³ of H₂O, Therefore , 6.022 ˣ 10²³ molecule of water occupy volume = 18 ml, Therefore 1 molecule of water occupy volume = 18 / 6.022 ˣ 10²³ = 2.99 ˣ 10⁻²³.

admin:

Related Questions

  1. Phenyl isocyanide test is used to identify
  2. A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated.
  3. What is the weight of oxygen required for the complete combusion of 2.8 kg of ethylene?
  4. The H – O – O bond angle in H₂O₂ is
  5. Which of the following depends on the path followed