The time period of a simple pendulum in a lift descending with constant acceleration g is

The time period of a simple pendulum in a lift descending with constant acceleration g is

Options

(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite

Correct Answer:

Infinite

Explanation:

When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.

admin:

Related Questions

  1. A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
  2. What is the amount of energy released by deuterium and tritium fusion?
  3. Dispersion of light is caused due to
  4. Find the maximum velocity with which a train can be moved on a circular track
  5. A bar magnet has a coercivity of 4×10³ Am⁻¹. It is placed inside a solenoid