The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is

Options

(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g

Correct Answer:

g/3

Explanation:

Weight when stationary = mg

Weight when moving downwards = m(g-a)

3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3