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The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours. The half-life of this radio nuclide is
Options
(a) 10 min
(b) 20 min
(c) 30 min
(d) 40 min
Correct Answer:
30 min
Explanation:
In 4 × T₁/₂, N = (N₀ / 2) × (1 / 2) × (1 / 2) × (1 / 2)
= N₀ / 16 4 × T₁/₂ = 2 hrs.
⇒ T₁/₂ = 30 min
