The phase difference between two points seperated by 0.8 m in a wave of frequency

The Phase Difference Between Two Points Seperated By 08 M Physics QuestionThe Phase Difference Between Two Points Seperated By 08 M Physics Question

The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is

Options

(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s

Correct Answer:

384 m/s

Explanation:

Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.

AddThis Website Tools
admin:

Related Questions

  1. A 0.01 H inductor and √3 πΩ resistance are connected in series
  2. A force of 10N is applied on a body for 3 sec and the corresponding displacement 6 m.
  3. If a star converts all helium in its core to oxygen, then energy released per oxygen
  4. An object is seen through a simple microscope of focal length 12 cm.
  5. A juggler maintains four balls in motion,making each of them to rise