The momentum of a photon of energy 1 MeV in kg m/s will be

The momentum of a photon of energy 1 MeV in kg m/s will be

Options

(a) 5 x 10⁻²²
(b) 0.33 x 10⁶
(c) 7 x10⁻²⁴
(d) 10⁻²²

Correct Answer:

5 x 10⁻²²

Explanation:

Energy of photon E = 1 MeV

Momentum of photon p = E / c

p = E / c = (1 × 10⁶ × 1.6 × 10⁻¹⁹J) / 3 × 10⁸ ms⁻¹

= 0.53 × 10⁻²¹ = 5 × 10⁻²² kg m/s.

admin:

Related Questions

  1. Two metal spheres of radii 0.01m and 0.02m are given a charge of 15mC and 45mC
  2. If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
  3. A projectile is fired at 30°. Neglecting friction, the change in kinetic energy when
  4. The time period of bar magnet is doubled when magnetic field is reduced
  5. A small rod of bismuth is suspended freely between the poles of a strong electromagnet.