The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.

The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)

Options

(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m

Correct Answer:

0.157 m

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
  2. If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
  3. If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
  4. A particle moves with constant speed v along a circular path of radius r and completes
  5. In Young’s double slit experiment the distance between the slits and the screen