The ionization energy of Li⁺⁺ is equal to

Options

(a) 9hcR
(b) 6hcR
(c) 2hcR
(d) hcR

Correct Answer:

9hcR

Explanation:

Ionisation energy of Li⁺⁺ = 9hcR

Ionisation energy = RchZ² = Rhc(3)² = 9hcR [as Z = 3 for Li⁺⁺]