The first ionization potentials (eV) of Be and B respectively are

Options

(a) 8.29, 9.32
(b) 9.32, 9.32
(c) 8.29, 8.29
(d) 9.32, 8.29

Correct Answer:

9.32, 8.29

Explanation:

First ionisation potential of Be is greater than boron due to following configuration ₄Be=1s²,2s² ₅B=1s²,2s²2p¹ Order of attraction of electrons towards nucleus 2s>2p, so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2p orbital