The equivalent resistance of two resistors connected in series is 6 Ω

The equivalent resistance of two resistors connected in series is 6 Ω and their parallel equivalent resistance is 4/3Ω. What are the values of resistances?

Options

(a) 4Ω,6Ω
(b) 8Ω,1Ω
(c) 4Ω,2Ω
(d) 6Ω,2Ω

Correct Answer:

4Ω,2Ω

Explanation:

Let the values of resistance be R₁ and R₂, respectively.
When R₁ and R₂ resistance are series, then
R₁ + R₂ = 6 (according to question) ——(i)
When R₁ and R₂ resistance are parallel, then
R₁R₂ / R₁+R₂ = 4 / 3 ——(ii)
From the equation (i), we get
R₁R₂ / 6 = 4 / 3 ⇒ R₁R₂ = 4 × 3 ⇒ R₁R₂ = 8 —–(iii)
We know that,
R₁ – R₂ = √[(R₁ + R₂)² – 4R₁R₂] = √[36 – 4 × 8] = √4 = 2
From equation (i) and (iv), we get
R₁ = 4 Ω, R₂ = 2 Ω

admin:

Related Questions

  1. Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
  2. In a parallel plate capacitor of capacitance C, a metal sheet is inserted
  3. The weight of a body on surface of earth is 12.6 N. When it is raised to a height
  4. The period of oscillation of a mass M suspended from a spring of negligible mass is T
  5. The mean radius of the earth is R, its angular speed on its own axis is ?