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The energy released by the fission of one uranium atom is 200 MeV.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is

Options

(a) 2×10¹¹
(b) 10¹¹
(c) 10¹⁰
(d) 2×10¹⁰

Correct Answer:

2×10¹¹

Explanation:

Let there is n number of fission per second produces a power of 6.4 W, then

n × 200 × 10⁶ × 1.6 × 10⁻¹⁹ Js⁻¹ = 6.4 Js⁻¹

.·. n = 6.4 / 200 × 10⁻¹³ × 1.6 = 4 / 2 × 10¹¹

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