The energy released by the fission of one uranium atom is 200 MeV.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is

Options

(a) 2×10¹¹
(b) 10¹¹
(c) 10¹⁰
(d) 2×10¹⁰

Correct Answer:

2×10¹¹

Explanation:

Let there is n number of fission per second produces a power of 6.4 W, then

n × 200 × 10⁶ × 1.6 × 10⁻¹⁹ Js⁻¹ = 6.4 Js⁻¹

.·. n = 6.4 / 200 × 10⁻¹³ × 1.6 = 4 / 2 × 10¹¹

admin:

Related Questions

  1. Two identical capacitors each of capacitance 5 mF are charged potentials 2 kV and 1 kV
  2. Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
  3. An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
  4. A body with mass 5 kg is acted upon a force F=(-3i+4j) N.If its initial velocity at
  5. If r be the distance of a point on the axis of a magnetic dipole from its centre