The energy released by the fission of one uranium atom is 200 MeV.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is

Options

(a) 2×10¹¹
(b) 10¹¹
(c) 10¹⁰
(d) 2×10¹⁰

Correct Answer:

2×10¹¹

Explanation:

Let there is n number of fission per second produces a power of 6.4 W, then

n × 200 × 10⁶ × 1.6 × 10⁻¹⁹ Js⁻¹ = 6.4 Js⁻¹

.·. n = 6.4 / 200 × 10⁻¹³ × 1.6 = 4 / 2 × 10¹¹

admin:

Related Questions

  1. The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
  2. A liquid boils when its vapour pressure equals
  3. Sodium and copper have work function 2.3 eV and 4.5 eV respectively
  4. A coil of self-inductance L is connected in series with a bulb B and an AC source
  5. A photoelectric surface is illuminated successively by monochromatic light of wavelength