The energy released by the fission of one uranium atom is 200 MeV.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is

Options

(a) 2×10¹¹
(b) 10¹¹
(c) 10¹⁰
(d) 2×10¹⁰

Correct Answer:

2×10¹¹

Explanation:

Let there is n number of fission per second produces a power of 6.4 W, then

n × 200 × 10⁶ × 1.6 × 10⁻¹⁹ Js⁻¹ = 6.4 Js⁻¹

.·. n = 6.4 / 200 × 10⁻¹³ × 1.6 = 4 / 2 × 10¹¹

admin:

Related Questions

  1. The electrons are emitted in the photoelectric effect from a metal surface
  2. A astronomical telescope has objective and eye-piece of focal lengths
  3. A 5 watt source emits monochromatic light of wavelength 5000Å. When placed
  4. A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
  5. A lens having focal length f and aperture of diameter d forms an image of intensity I