Navigate

The energy released by the fission of one uranium atom is 200 MeV.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is

Options

(a) 2×10¹¹
(b) 10¹¹
(c) 10¹⁰
(d) 2×10¹⁰

Correct Answer:

2×10¹¹

Explanation:

Let there is n number of fission per second produces a power of 6.4 W, then

n × 200 × 10⁶ × 1.6 × 10⁻¹⁹ Js⁻¹ = 6.4 Js⁻¹

.·. n = 6.4 / 200 × 10⁻¹³ × 1.6 = 4 / 2 × 10¹¹

GJ2015
admin:

Related Questions

  1. “On flowing current in a conducting wire the magnetic field is produced around it”.
  2. A comb run through one’s dry hair attracts small bits of paper. This is due to
  3. The velocity of sound is V, in air. If the density of air is increased to four times
  4. Charge q is uniformly spread on a thin ring of radius R. The ring rotates
  5. Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact