The distance of the closest approach of an alpha particle fired at a nucleus with kinetic energy K is r₀. The distance of the closest approach when the α particle is fired at the same nucleus with kinetic energy 2K will be

Options

(a) 4r₀
(b) r₀/2
(c) r₀/4
(d) 2r₀

Correct Answer:

r₀/2

Explanation:

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