The activation energy of a reaction at a given temperature is found to be 2.303

The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol⁻¹.The ratio of rate constant to the Arrhenius factor is

Options

(a) 0.01
(b) 0.1
(c) 0.02
(d) 0.001

Correct Answer:

0.1

Explanation:

Arrhenius equation K=A.e(-Eₐ/RT)

⇒In K =In A -Eₐ/RT slop = -Eₐ/R

so,activation energy of reaction can be determined from the slop of In K vs 1/T

admin:

Related Questions

  1. Which of the following is broad spectrum drug
  2. In the reaction : 2P₂O₅ + 2HNO₃ → P₄O₁₀ + x, the term x is
  3. The reaction in which phenol differs from alcohol is
  4. Which of the following complexes is used to be as an anticancer agent
  5. When cold potassium permanganate (KMnO₄) is added to ethylene gives