The activation energy of a reaction at a given temperature is found to be 2.303

The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol⁻¹.The ratio of rate constant to the Arrhenius factor is

Options

(a) 0.01
(b) 0.1
(c) 0.02
(d) 0.001

Correct Answer:

0.1

Explanation:

Arrhenius equation K=A.e(-Eₐ/RT)

⇒In K =In A -Eₐ/RT slop = -Eₐ/R

so,activation energy of reaction can be determined from the slop of In K vs 1/T

admin:

Related Questions

  1. Which of the following pairs show reverse properties on moving along
  2. Magnetic moment of (NH₄)₂[MnBr₄] is ___ BM
  3. XeF₂ is isostructural with:
  4. When ethanal is treated with Fehling’s solution. it gives a precipitate of
  5. When chloroform is exposed to light and air, it forms