Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be[Take specific heat of water=1 cal g⁻¹ °C⁻¹ and latent heat of steam=540 cal g⁻¹]

Options

(a) 24 g
(b) 31.5 g
(c) 42.5 g
(d) 22.5 g

Correct Answer:

22.5 g

Explanation:

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