Specific conductance of 0.1 M nitric acid is 6.3 ˣ 10⁻² ohm⁻¹ cm⁻¹.The molar conductance of solution is
Options
(a) 630 ohm⁻¹ cm² mol⁻¹
(b) 315 ohm⁻¹ cm² mol⁻¹
(c) 100 ohm⁻¹ cm² mol⁻¹
(d) 6,300 ohm⁻¹ cm² mol⁻¹
Correct Answer:
630 ohm⁻¹ cm² mol⁻¹
Explanation:
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630 option A.
Because ∆m=conductivity x 1000 divided by moralirty.